Each question gives you four equations — three are correct, one is wrong. Your job is to find it. This page teaches you the technique so you can spot errors quickly and confidently.
For students who can solve equations, but need practice spotting the one step that breaks equality.
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Students are given four equations using similar digit arrangements where three equations balance correctly and one is mathematically false. They must evaluate both sides of each equation independently using the order of operations to identify the incorrect statement. Here is a worked example.
Question: Identify the incorrect calculation.
A. 9 × 5 + 62 = 95 + 6 × 2
B. 7 × 7 + 45 = 77 + 4 × 5
C. 3 × 4 + 57 = 34 + 5 × 7
D. 6 × 4 + 75 = 64 + 7 × 5
What it's testing: Rule 1 and Rule 2 — calculating both sides using correct order of operations.
Check option B (it looks plausible but has a subtle error):
LHS: 7 × 7 + 45 = 49 + 45 = 94
RHS: 77 + 4 × 5 = 77 + 20 = 97
94 ≠ 97, so option B is wrong. No need to check further.
Tip: Work out 4 × 5 before adding 77. Then compare the two totals.
As shown in the example above, each problem tests whether both sides of an equation evaluate to the same value. Use these key rules and strategies to test options quickly without guessing.
Never assume the equation is true just because it looks balanced. Calculate the left-hand side (LHS) and the right-hand side (RHS) separately.
Example: 3 × 4 + 57 vs 34 + 5 × 7 → LHS: 12 + 57 = 69; RHS: 34 + 35 = 69 ✓
These questions use multiplication and addition without brackets, so multiply first, then add. Do this on each side of the equals sign.
Example: 7 × 7 + 45: do 7 × 7 = 49 first, then 49 + 45 = 94 — not 7 × (7 + 45).
The same digits can make different totals when they are grouped differently. Calculate both sides to check whether they are equal.
Tip: Compare the answers, not just the digits. Different digits can also give equal answers: 2 + 3 = 4 + 1.
Three of the four equations balance perfectly. The task is to find the single one that doesn't. Once you find the error, stop — you don't need to verify every option.
Strategy: Start with the option that looks most suspicious or that you can calculate fastest. If it's wrong, you're done.
Practise checking equations when both sides look visually similar, then learn why equal sub-products do not guarantee that the full statements balance.
Question: Identify the incorrect calculation.
A. 6 × 9 + 25 = 69 + 2 × 5
B. 2 × 8 + 39 = 28 + 3 × 9
C. 7 × 9 + 54 = 79 + 5 × 4
D. 5 × 9 + 26 = 59 + 2 × 6
What it's testing: Rules 1–3 — checking the totals even when both sides have a similar layout.
Check option C:
LHS: 7 × 9 + 54 = 63 + 54 = 117
RHS: 79 + 5 × 4 = 79 + 20 = 99
117 ≠ 99, so option C is wrong.
Compare with option A: LHS: 6 × 9 + 25 = 54 + 25 = 79; RHS: 69 + 2 × 5 = 69 + 10 = 79 ✓
Tip: A similar layout does not guarantee equal answers. Work out both sides.
Question: Identify the incorrect calculation.
A. 8 × 7 + 43 = 87 + 4 × 3
B. 7 × 8 + 27 = 78 + 2 × 7
C. 5 × 5 + 66 = 55 + 6 × 6
D. 7 × 2 + 94 = 72 + 9 × 4
What students do wrong: They see 8 × 7 in option A and 7 × 8 in option B and assume both equations must be correct. Swapping the numbers in a multiplication gives the same answer, but other numbers in these equations also change.
Check option B:
LHS: 7 × 8 + 27 = 56 + 27 = 83
RHS: 78 + 2 × 7 = 78 + 14 = 92
83 ≠ 92, so option B is wrong.
Check option A to confirm it's valid: LHS: 8 × 7 + 43 = 56 + 43 = 99; RHS: 87 + 4 × 3 = 87 + 12 = 99 ✓
The rule: Check each equation separately. Option A gives 99 on both sides, so it is correct. Option B gives 83 on the left and 92 on the right, so it is incorrect. The fact that both options contain a multiplication worth 56 does not make both equations correct.