Line Graph Practice Test Worksheets

Line graph questions ask you to compare line segments on a coordinate grid. The key is to calculate gradients carefully, then use the rules for parallel lines, perpendicular lines, translations, and missing coordinates.

For students who can read plotted points, but lose marks using gradients, parallel lines, perpendicular lines, and translations.

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What Do Line Graph Questions Look Like?

Line graph questions ask you to compare line segments plotted on a coordinate grid. You must calculate gradients, test whether lines are parallel or perpendicular, and determine translations or missing endpoint coordinates. Here is a worked example.

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Example

Check Whether Two Lines Are Parallel

Question: Line A passes through (3, 4) and (6, 2). Line B passes through (1, 7) and (4, 5). Are lines A and B parallel?

0 x y 1 2 3 4 5 6 7 8 1 2 3 4 5 6 7 (1, 7) (4, 5) B A (3, 4) (6, 2)

Worked Method

Step 1: Gradient of line A = 2 - 46 - 3 = -23.

Step 2: A parallel line must also have gradient -23.

Step 3: Line B, through (1, 7) and (4, 5), has gradient 5 - 74 - 1 = โˆ’23, matching line A.

Step 4: At x = 4, line A has y = 4 โˆ’ 23 = 103, whereas line B has y = 5. They are distinct lines with equal gradients, so yes, they are parallel.

Tip: Use the same point order in the numerator and denominator. Reversing only one subtraction gives the wrong sign.

Rules to Help You Solve Line Graph Questions

The papers focus on coordinate line segments: finding gradients, comparing parallel lines, checking perpendicular lines, translating a line, and using a known gradient to find a missing coordinate:

๐Ÿ“ˆ Rule 1: Gradient is rise over run

Subtract the y-values, then divide by the change in x-values, keeping the points in the same order in both subtractions. A horizontal line has gradient 0. A vertical line has an undefined gradient because its change in x is 0; do not divide by zero.

Example: From (3, 4) to (6, 2), gradient = 2 - 46 - 3 = -23.

0xy246812345 (3, 4) (6, 2) run +3 rise โˆ’2 Gradient = โˆ’2 รท 3 = โˆ’ 2 3

โˆฅ Rule 2: Parallel lines have the same gradient

Distinct non-vertical parallel lines have equal gradients and different y-intercepts (where they cross the y-axis). Equal gradients and equal y-intercepts mean the segments lie on the same straight line. Distinct vertical lines are parallel to each other.

Example: A line with gradient -12 is parallel to any other line with gradient -12 and a different y-intercept.

0xy246812345 gradient โˆ’ 1 2 gradient โˆ’ 1 2 Same gradient; intercepts 5 and 3

โŠฅ Rule 3: Perpendicular gradients multiply to -1

For a line with a non-zero, defined gradient, flip the fraction and change the sign to find the perpendicular gradient. These two gradients multiply to -1. The special case is a horizontal line and a vertical line: they are perpendicular, but the vertical gradient is undefined.

Example: A line with gradient -1 has perpendicular gradient 1.

0xy246812345 gradient โˆ’1 gradient 1 90ยฐ โˆ’1 ร— 1 = โˆ’1: perpendicular

โ†” Rule 4: Translations move both endpoints

Apply the same translation vector to each endpoint: use the horizontal change for each x-coordinate and the vertical change for each y-coordinate.

Example: Moving (5, 1) and (7, 2) two left and one up gives (3, 2) and (5, 3).

0xy246812345 (5, 1) (7, 2) (3, 2) (5, 3) Both endpoints: x โˆ’ 2, y + 1

Two More Worked Examples

Example

Translate Both Endpoints

Question: A line segment joins (5, 1) to (7, 2). Find its new endpoints after a translation 2 units left and 1 unit up.

0 x y 1 2 3 4 5 6 7 8 1 2 3 4 5 6 7 (5, 1) (7, 2) (3, 2) (5, 3) Move each endpoint 2 left and 1 up.

Worked Method

Step 1: A move 2 left and 1 up means x - 2 and y + 1.

Step 2: (5, 1) becomes (3, 2).

Step 3: (7, 2) becomes (5, 3).

Tip: Translate both endpoints. Moving only one endpoint does not correctly translate the whole segment.

Classic Trap

Use the Parallel Gradient to Find a Missing Coordinate

Question: A second line joins (2, 5) to (6, y). If it is parallel to a line from (3, 1) to (7, 2), what is y?

0 x y 1 2 3 4 5 6 7 8 1 2 3 4 5 6 7 (3, 1) (7, 2) (2, 5) (6, y) Run = 4, rise = 1. Add the rise: y = 5 + 1 = 6.

Worked Method

Step 1: Gradient of the first line = 2 - 17 - 3 = 14.

Step 2: The second line must also have gradient 14.

Step 3: Its run is 6 - 2 = 4, so the rise must be 1.

Step 4: y = 5 + 1 = 6.

Tip: The rise is the change in y, not the final y-coordinate. A rise of 1 means add 1 to the starting y-coordinate of 5, giving y = 6.

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