Compound Cuboid Volume Practice Test Worksheets

Build confidence with printable compound cuboid volume worksheets and focused maths practice tests. Students learn to split stacked solids into cuboids, subtract cut-out sections, and find missing dimensions while improving accuracy with multi-step 3D shape problems.

For students who know length × width × height, but need practice applying it to more complex 3D shapes.

Three overlapping pages from the Compound Cuboid Volume practice pack
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What Do Compound Cuboid Volume Questions Look Like?

Students are given 3D composite shapes made from rectangular prisms and must find the total volume or an unknown side length. Questions often involve splitting stacked blocks or subtracting a missing cut-out section to calculate the correct measurement. Here is a worked example.

Example

Add Two Stacked Cuboids

Question: A 4 cm × 2 cm × 4 cm cuboid sits on a 9 cm × 2 cm × 4 cm cuboid. What is the total volume?

Split the stack into two non-overlapping cuboids
9 cm4 cm2 cm2 cm4 cmTopBottomBoth blocks share the same depth: 4 cm

Worked Method

Step 1: Bottom cuboid = 9 × 2 × 4 = 72 cm³.

Step 2: Top cuboid = 4 × 2 × 4 = 32 cm³.

Step 3: Total volume = 72 + 32 = 104 cm³.

Tip: Split a stacked shape into separate cuboids and add their volumes. Do not count an overlapping region twice.

Rules to Help You Solve Compound Cuboid Volume Questions

As shown in the example above, breaking a compound 3D solid into simple rectangular blocks makes finding total volume straightforward. Use these core rules to approach stacked shapes, cut-outs, and missing measurements systematically.

📦 Rule 1: Volume = length × width × height

9 cm2 cm4 cm

Calculate each rectangular block separately before combining the results.

Example: A 9 cm × 2 cm × 4 cm block has volume 72 cm³.

➕ Rule 2: Split stacked solids into blocks

32 cm³72 cm³32 + 72 = 104 cm³

For a stepped or stacked shape, add the volume of each non-overlapping cuboid.

Example: 32 cm³ + 72 cm³ = 104 cm³.

➖ Rule 3: Subtract a cut-out cuboid

Full cuboid − removed block

When a corner is removed, calculate the full outer cuboid and subtract the missing block.

Example: 140 cm³ − 24 cm³ = 116 cm³.

↩ Rule 4: Work backwards for missing lengths

72 cm³xBase area = 36 cm²x = 72 ÷ 36 = 2 cm

For a missing cut-out height, find the removed volume and divide by the cut-out's width × depth. For an unknown shared depth, divide the remaining solid's volume by its remaining front-face area.

Example: 72 cm³ ÷ 36 cm² = 2 cm.

Two More Worked Examples

Practise finding volume by subtracting a cut-out corner, then learn how to work backwards from a known volume to find a missing height.

Example

Subtract a Corner Cut-Out

Question: A cuboid is 7 cm wide, 5 cm high, and 4 cm deep. A corner is removed through its full depth, leaving an upper ledge 4 cm wide. The cut-out is 2 cm high. What volume remains?

See the solid as a full cuboid minus one corner
7 cm5 cm4 cm4 cm2 cmDashed edges show the removed corner

Worked Method

Step 1: Full cuboid = 7 × 5 × 4 = 140 cm³.

Step 2: Cut-out width = total width − upper ledge width = 7 − 4 = 3 cm.

Step 3: Cut-out cuboid = 3 × 2 × 4 = 24 cm³.

Step 4: Remaining volume = 140 − 24 = 116 cm³.

Tip: Subtraction works well when the shape is easiest to see as one complete cuboid with a corner missing.

Example

Work Backwards to Find a Missing Length

Question: A cuboid is 10 cm wide, 7 cm high, and 6 cm deep. A corner is removed through its full depth, leaving an upper ledge 4 cm wide. The remaining volume is 348 cm³. Find the cut-out's missing height, x.

Find the removed volume before solving for x
10 cm7 cm6 cm4 cm xRemaining volume: 348 cm³Dashed edges show the removed corner

Worked Method

Step 1: Full cuboid = 10 × 7 × 6 = 420 cm³.

Step 2: Cut-out volume = 420 − 348 = 72 cm³.

Step 3: Cut-out width = total width − upper ledge width = 10 − 4 = 6 cm.

Step 4: Cut-out base area = width × depth = 6 × 6 = 36 cm².

Step 5: Divide the removed volume by its base area: x = 72 ÷ 36 = 2 cm.

Answer: x = 2 cm.

Tip: Use the removed 72 cm³ when finding the cut-out height. Dividing the remaining 348 cm³ by the cut-out base area mixes measurements from different solids.

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